*Doh!* basetype() would never call _sprintf, of course. sprintf("%t"...) would always do it.
/ Martin Stjernholm, Roxen IS
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2002-11-28 23:01: Subject: CHANGES line of the day
No, it's not committed. I suggested that you add that so that one can have a basetype function that doesn't call _sprintf. Calling sprintf("%t",x) doesn't solve that, since it calls _sprintf.
/ Martin Nilsson (hehe Torgny)