8 Sep
2014
8 Sep
'14
12:21 p.m.
Arne Goedeke wrote:
a += b is a shorthand for a = a + b, so the refs==1 check is the only correct condition for when to use the `+= lfun. The `+= lfun therefore is _not_ operator overloading for +=, but rather an optimization for when a has only one reference.
Yes, that seems to describe what happens. That is not what someone would expect that implements an `+= lfun on an object.
The question now remains: - Do we agree this is a bug? - Or do we document that this is a feature? - Or maybe we already documented it as a feature and I just didn't see it.
--
Stephen.