Your examples doesn't show it, but elements are removed from the beginning towards the end in both arrays. Then the results are concatenated. E.g. ({1})^({1,2,1}) produces ({2,1}), not ({1,2}).

/ Martin Stjernholm, Roxen IS

Previous text:

2004-09-19 02:34: Subject: order of elements after: a^b

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hi,

when i combine two arrays using exclusive or (^) the order of the resulting elements appears to be like (a+b)-(elements from both):

a = ({ 1, 7, 2, 8, 4 }); b = ({ 2, 1, 3, 0, 5 }); a^b is ({ 7, 8, 4, 3, 0, 5 })

however if there are doubles a = ({ 1, 7, 2, 5, 4 }); b = ({ 2, 1, 3, 5, 5 }); a^b is ({ 7, 4, 3, 5 }) b^a is ({ 3, 5, 7, 4 })

one of them remains. what's the strategy here?

it looks like from both arrays it removes always the same number of elements.

greetings, martin.

/ Brevbäraren