It's call-by-reference insofar that the string isn't copied in the call to foo(), but it's not call-by-reference in the sense that modifying a formal argument also modifies the actual argument variable in the caller.

Yes, use a value that you can modify destructively.

void foo(mapping m) { m->s=m->s+"!"; }

void main() { mapping m=(["s":"Hello World"]); foo(m); write(m->s+"\n"); }

/ Mirar

Previous text:

12527646 2004-11-03 19:54 /14 lines/ Peter Lundqvist (disjunkt) Recipients: Pike (-) help Subject: call by reference

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I was under the impression that call by reference was default in pike, but it seems I've lived a lie. Is there a way to write

void foo(string s) { s=s+"!"; }

void main() { string a = "Hello World"; foo(a); write(a+"\n"); }

without returning a string from foo?

(12527646) /Peter Lundqvist (disjunkt) /----------------------------