20 Jan
2009
20 Jan
'09
11:21 p.m.
On Tue, Jan 20, 2009 at 11:15:02PM +0000, Martin Stjernholm, Roxen IS @ Pike developers forum wrote:
array a = ({0}); for (int i = 1; i < 1000; i++) a += ({i}); (To make the example simpler, I start out with the array ({0}) instead of the empty array ({}) since the empty array always is shared.)
is that actually making code faster or is it only to make the logic of the problem you are discussing simpler?
One alternative is to extend the array type to explicitly allow adding elements to the end destructively. It could perhaps look like this: a[sizeof (a)] = i;
what about possible code that expects this operation to fail?
mixed error = catch{ a[x] = i; }; if (error) write("ooops, we reached the end\n");
greetings, martin.