why not? Tools.Standalone["pike7.3.53"] is unlikely to exist,
True.
the default should be to simply run pike as is if nothing is found in Tools.Standalone.
Sooner or later this will clash with something someone uses. I currently have pikes called "aido", "roxen", "pike13", "aido-server", "snarf", "easyget" and "xeno".
besides, this could be an interresting way to invoke compatibility mode.
No thank you. To much unobvious magic.
/ Peter Bortas
Previous text:
2002-09-06 10:26: Subject: Re: -x
On Fri, Sep 06, 2002 at 01:25:05AM +0200, Marcus Comstedt (ACROSS) (Hail Ilpalazzo!) @ Pike (-) developers forum wrote:
Wouldn't work. What if I did a symlink 'pike7.3.53' pointing to a particular pike binary? I wouldn't want that to try to execute Tools.Standalone["pike7.3.53"].
why not? Tools.Standalone["pike7.3.53"] is unlikely to exist, the default should be to simply run pike as is if nothing is found in Tools.Standalone.
besides, this could be an interresting way to invoke compatibility mode.
greetings, martin.
/ Brevbäraren