j
k
j a
j l
...That check has already been performed when lfun::`==() gets called. Does this mean, if lfun::`==() gets called the compared objects are actually NOT the same object? Otherwise the call would have been avoided?
That check has already been performed when lfun::`==() gets called.
Does this mean, if lfun::`==() gets called the compared objects are actually NOT the same object? Otherwise the call would have been avoided?
Correct.
--- Ludger Merkens
Back to the thread
Back to the list
