Bug in replace

Eh, "." is a string literal containing a single dot. "\b" is a string literal containing a single backspace. The first is printed as ".", the second is printed as "\b". Replaceing a dot with a dot of course does nothing.

/ Marcus Comstedt (ACROSS) (Hail Ilpalazzo!)

Previous text:

2004-09-09 14:43: Subject: Bug in replace

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Hi,

Replace doesn't seem to like . :

string s = Pike v7.6 release 13 running Hilfe v3.5 (Incremental Pike Frontend)

...

string s = "foo.bar.com"; replace(s, ".", ".");

(1) Result: "foo.bar.com"

...

replace(s, "a", ".");

(2) Result: "foo.b.r.com"

...

replace(s, "a", "\b");

(3) Result: "foo.b\br.com"

It does the same with 7.2, 7.4

/ David

/ Brevbäraren