3 Dec
2002
3 Dec
'02
2:55 p.m.
Today you have that "consistency" for the right element instead:
1. if (bar[-3] == 4) x(); 2. bar = foo | bar; 3. if (bar[-3] == 4) x();
You can't have both, and I don't see why one would be more important than the other.
/ Marcus Comstedt (ACROSS) (Hail Ilpalazzo!)
Previous text:
2002-12-03 20:47: Subject: `| and order on arrays
The consistency is between the first and third steps below:
- if (foo[2] == 3) x();
- foo |= bar;
- if (foo[2] == 3) x();
/ Martin Stjernholm, Roxen IS